Traverse paths in DIN/ISO

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Thread: Traverse paths in DIN/ISO

  1. #1
    butscheronie's Avatar
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    Angry

    Unfortunately I’m not really fit in free contour programming.

    Could anybody tell me how it’s possible to program a straight line under an angle with a defined length of 72,8mm (see picture)?

    I think I should begin as follows:

    G1 ANG=15,95…………. And then?



  2. #2
    Registered dekoboy's Avatar
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    Default

    Unfortunately I’m not really fit in free contour programming.

    Could anybody tell me how it’s possible to program a straight line under an angle with a defined length of 72,8mm (see picture)?

    I think I should begin as follows:

    G1 ANG=15,95…………. And then?
    Hello butscheronie

    You also need a measurement at the end point (X or Y).

    Maybe you should make it with polar coordinates…

    G1 X0 Y0
    G111 X0 Y0 ; declare Pol (absolute)
    G1 AP=15.95 RP=72.8 ; rack in line with angle 15.95 and length 72.8

    I hope it’ll help

    Regards, dekoboy



  3. #3
    butscheronie's Avatar
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    Default

    I imagined something like this…

    I’ll try it out tomorrow.

    Thanks for now



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Traverse paths in DIN/ISO

Traverse paths in DIN/ISO