Geesch...they have the torque / rpm curves in the specifications....look at them. They are steppers so the torque will vary with speed....they are inversely proportional.....the faster you go ...the less torques.....etc.
If using the Xylotex bipolar I want as much power from my steppers without gearing them down. AutomationDirect has --> "Stepper motor, 434 oz-in holding torque, 2.8 A/phase, 1.8 degrees / fullstep (200 steps/revolution), NEMA size 34. 4 leads terminated with a connector."
Link to motor
So how much torque can I expect from this setup and how do you figure that out.
Any other suggestions are welcome, I just don't want to spend a fortune on the drive. Any help is appreciated!
Geesch...they have the torque / rpm curves in the specifications....look at them. They are steppers so the torque will vary with speed....they are inversely proportional.....the faster you go ...the less torques.....etc.
I know they have the torque but at the amps the Xylotex can supply am I looking at 2.5/2.8*rated torque. Also, this much torque at only 2.8 amps, are these things gona run slow?
With a Xylotex, they probably will. You probably need a drive you can use a higher voltage with. And gearing a stepper may not help get you more speed, because as the stepper spins, for example, twice as fast to double your torque, it may lose half its torque from spinning faster, giving you no gain.Originally Posted by butwillitwork
Gerry
Mach3 2010 Screenset
http://home.comcast.net/~cncwoodworker/2010.html
(Note: The opinions expressed in this post are my own and are not necessarily those of CNCzone and its management)
Thanks, that is exactly what I needed to know. This place is great>