little lost on G03 between Mach and PCNC 1100 Mach...

[Spinnetti]

So, I'm trying to hand code a part, and have it all working except for one profile. I'm using .5" round stock, cutting it square, cutting side pockets and drilling it. On the end of the part I'm trying to cut a little hump with a .125 cutter, and the profile shows fine in master cam, but is all off on the machine (Tormach 1100).. Given the Parms in the attached picture, what should the G03 line look like? I've figured out tool changes and tool offsets this weekend, but this has got me scratchin my head.

Here's the pertinent lines out of mastercam.. doesn't make sense to me. The first and last lines should be the entry and exit from the cut where x is already at the baseline cut depth.
N200 Y.1719
N210 G03 Y.3281 I-.2375 J.0781
N220 G01 Y.425

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[Steve Seebold]

I posted it in my GibbsCam with a ruff pass leaving .005 for finish and it says to do:
(RUFF)
G0 G90 X.8298 Y.5577
G43 H1 Z.1 M8
G1 Z-.04 F75.
Y.3577 F35.
Y.2616
G2 Y.1039 I-.2425 J-.0789
G1 Y.0077
Y-.1923
G0 Z.5
( FINISH)
G0 X.8248 Y.5577
Z.1
G1 Z-.04 F75.
Y.3577 F35.
Y.2608
G2 Y.1047 I-.2375 J-.0781
G1 Y.0077
Y-.1923
G0 Z.5

Hope this helps.

[Spinnetti]

I posted it in my GibbsCam with a ruff pass leaving .005 for finish and it says to do:
G0 X.8248 Y.5577
Z.1
G1 Z-.04 F75.
Y.3577 F35. <-----
Y.2608 <----- Why not just one move?
G2 Y.1047 I-.2375 J-.0781
G1 Y.0077
Y-.1923 <----- Given that the part is symetric, shouldn't the entry and exit moves be the same, just one + and one - ?
G0 Z.5

Hope this helps.

Thanks Steve... I'm doing G3, for a climb cut, but the format of Y I J is what I was checking and still not clear how those are used to cut an arc?

I notice your CAM does the same redundant moves too.. wonder why?

[Zetopan]

I'm doing G3, for a climb cut, but the format of Y I J is what I was checking and still not clear how those are used to cut an arc?

G03 is a Clockwise Circular Interpolation command. The Y I J parameters in
your example are interpreted in the following way:

Perform a Clockwise Circular Arc move from the current position to the
given Y position with the center of the arc located at I,J relative to the
current (starting) position.

In other words, I and J are offsets relative to the current position specifying
where the arc center is located, and X and/or Y (only Y in your example) are
the stopping location of the end of the arc. The arc starts at the current
location and it stops when Y is reached while moving clockwise around the
arc center.

Simply perform a Google search for "G Code syntax" to learn about all of the
G and M code commands. Here is the location of one example:
http://www.imsrv.com/deskcnc/DeskCNC%20G-code.pdf

[Spinnetti]

Thanks for the code and info... I had googled it, but didn't quite "get it".. You've helped me over the hump - I wasn't catching the IJ being the arc center with the radius being derived from the difference from the center point and the terminus of the arc - now I get it!...

Thanks! - I hope to try again in a couple nights, and if it works I can do my parts run and be happy ...