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#1
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Hi there I want to ask about driving stepper motor. If i consider the following scheme to drive the stepper motor [ Attached ]: i use two limit resistor to limit the current at 1 A for each coil . If i want to run the motor in FALL STEP mode, each coil can take 1A by the resistors, no problem. But if i want to run the motor in HALF STEP mode, there are two cases which the current must be 2A a flows through each resistor ( that when sequences active the coils 1 and 2 OR 3 and 4 ) to be divided to 1A in each coil. That means the value of the limit resistor must be decreased . Then, in the other two cases in the sequences that the current must be 1A through each resistor ( that when sequences active the coils 2 and 3 OR 1 and 4 )[ like running in fall step mode] . That means the value of the limit resistor must be increased . my question is How can i use 2 limit resistors and keep the current at 1A in each coil in all sequences when running in HALF STEP mode? Are there any mistakes in my scheme ?? thank you. |
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#2
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| The motor will not run in the 1 2 3 4 sequence but more in the 1 3 2 4 sequence. 1 & 2, and 3 & 4 will never be energized at the same time. http://www.usna.edu/EE/ee461/Homewor...AllPhases1.gif Your schematic is Ok if you want to run the stepper in half or full step mode (even wave mode) using some ballast resistors. Last edited by AlainB; 02-27-2010 at 04:30 PM. |
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