Well a good place to learn quite a LOT is in this book it pretty much is the Bible for the machining world.
I'm very much interested in router design and I should like to know the following details about it.
1- What are typical forces generated by a tool when milling aluminum? I mean x,y,z maximum levels of forces for milling aluminum.
2- Where I could find detailed technical information or data about this subject?
Anybody knows a good mechanical engineering handbook about milling?
Thank you in advanced for your help
try this , it should give you a general idea of the cutting force http://metalworking.com/Shareware/machine_design.zip
A poet knows no boundary yet he is bound to the boundaries of ones own mind !! ........
"A comparison of analytical cutting force models" published by WIAS
where one can find very simple models to compute cutting forces during end milling aluminum as a function of chip thickness and axial depth of cut. If anyone is interested I can give details about it.
Now I can continue with my design
call me interested...If anyone is interested I can give details about it.
Cutting forces, according Kinzle-Victor model, can be predicted through this formula Fi=Ki*a*h^(1-mi)
Where “Fi” is force in N, “a” is the load per tooth in (mm) , “h” is the depht of cut in (mm) and “Ki” and “ mi” are constants that depend of “h” values
The Kinzle-Victor model predicts tangential Ft and radial Fr milling cutting forces
For end milling aluminum the values of constants Ki and mi are:
Kr=39 for 0.001 < h <0.01 ; Kr=99 for 0.01 <= h <0.1 ; Kr=298 for 0.1 <= h <1
Kt=336 for .001 < h <.01; Kt=493 for 0.01 <= h <0.1 ; Kt=667 for 0.1 <= h <1
mr= 1 for 0.001 < h <0.01; mr=0.8 for 0.01 <= h <0.1; mr=0.32 for 0.1 <= h <1
mt= 0.53 for 0.001 < h <0.01 ; mt=0.45 for 0.01 <= h <0.1; mt=0.32 for 0.1<= h <1
For example for cutting depht of 0.5 mm and a load per tooth of 0.1 mm the forces for aluminum are:
Model computes tangential and radial forces located at xy plane but doesn’t compute axial force at z axis and I don’t know if are average or peak forces
Using Jim Tuttle program with the same conditions and a rake angle of 20º the force predicted is 26 lbs or 115 N. I don’t know if this 115 N force is the total force
thanks for posting it.