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#1
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I'm very much interested in router design and I should like to know the following details about it. 1- What are typical forces generated by a tool when milling aluminum? I mean x,y,z maximum levels of forces for milling aluminum. 2- Where I could find detailed technical information or data about this subject? Anybody knows a good mechanical engineering handbook about milling? Thank you in advanced for your help -Francesc |
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#3
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| try this , it should give you a general idea of the cutting force http://metalworking.com/Shareware/machine_design.zip
__________________ A poet knows no boundary yet he is bound to the boundaries of ones own mind !! http://cnctoybox.org |
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#4
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"A comparison of analytical cutting force models" published by WIAS where one can find very simple models to compute cutting forces during end milling aluminum as a function of chip thickness and axial depth of cut. If anyone is interested I can give details about it. Now I can continue with my design -Francesc |
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#6
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Kinzle-Victor model for predicting end milling Aluminum cutting forces Cutting forces, according Kinzle-Victor model, can be predicted through this formula Fi=Ki*a*h^(1-mi) Where “Fi” is force in N, “a” is the load per tooth in (mm) , “h” is the depht of cut in (mm) and “Ki” and “ mi” are constants that depend of “h” values The Kinzle-Victor model predicts tangential Ft and radial Fr milling cutting forces For end milling aluminum the values of constants Ki and mi are: Kr=39 for 0.001 < h <0.01 ; Kr=99 for 0.01 <= h <0.1 ; Kr=298 for 0.1 <= h <1 Kt=336 for .001 < h <.01; Kt=493 for 0.01 <= h <0.1 ; Kt=667 for 0.1 <= h <1 mr= 1 for 0.001 < h <0.01; mr=0.8 for 0.01 <= h <0.1; mr=0.32 for 0.1 <= h <1 mt= 0.53 for 0.001 < h <0.01 ; mt=0.45 for 0.01 <= h <0.1; mt=0.32 for 0.1<= h <1 For example for cutting depht of 0.5 mm and a load per tooth of 0.1 mm the forces for aluminum are: Ft=Kt*a*h^(1-mt)=493*0.5*0.1^1-0.45=69 N F=Kr*a*h^(1-mr)=99*0.5*0.1^1-0.8=31 N Model computes tangential and radial forces located at xy plane but doesn’t compute axial force at z axis and I don’t know if are average or peak forces Using Jim Tuttle program with the same conditions and a rake angle of 20º the force predicted is 26 lbs or 115 N. I don’t know if this 115 N force is the total force |
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#8
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I find the standard size to be sort of small. A larger format would be easier to read. Steve |
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