
Originally Posted by
RomanLini
That's not bad. The mechanical advantage is given from the driving circumference, over the driven distance. Your driving circumference is a little less than 0.5" say 0.45" average, and you need to de-rate a lot for the friction (reduced drive efficiency). Also you need to de-rate for load forces and higher stepper speeds which have less torque.
I would say;
0.45*Pi/0.1 = 14.13 (perfect model)
then de-rate 50% for your leadnut friction and 50% for reduced motor torque;
14.13 * 0.5 * 0.5 = 3.53
So that's 160oz*3.5 = 560 oz force
If your leadnuts are some "tight" design like plastic nuts on the metal screw it might need derating some more, likewise if you have any bind on the moving parts, linear bearings etc.
Re the Z axis it helps to finalise most of the Z design as that will determine where the cutting tool bit is, and that determines where you need to have the moving table to get full cutting area.