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#1
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| How do I calculate this? I need to know how much torque is produced for a 45.6 in/oz servo using a 20:1 gear reduction.
__________________ Thank You, Paul G Site Owner-Webmaster- Administrator www.rfqwork.com www.cnczone.com www.welderzone.com |
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#2
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| Simple answer is it's 45.6 x 20. More force over a shorter distance is the same as less force over a longer distance. A more accurate answer is that the gearbox has losses so the calculation is 45.6x20x(efficiency of the gearbox) where Efficiency is, say 50% use 0.5. |
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#3
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| Paul, The output of the gear reduction should be: 45.6 * 20 = 912 In oz or 912 / 12 = 72 ft oz or 72 / 16 = 4.75 ft lb Hope this helps PS: I think your original units should be in oz of torque NOT in/oz???
__________________ Art AKA Country Bubba (Older Than Dirt) |
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