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| Linear and Rotary Motion Discuss ball/Acme screws, R&P, linear slides and theory here. |
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#1
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Hey every one, this is probably a redundant thread and I'm sorry but I tried to search for answers to my problem with no avail. I just finished building my first CNC router using Ebay (I know I know!) ballscrews. Its just for playing around in the garage so I figured these would be fine. Well after getting everything set up and the machine cutting out parts I noticed they are all coming out undersized. When I tell it to cut out a 2" circle, the circle actually comes out to be 1.915 in diameter. The ballscrews I bought are metric (16mm in diameter) From Ebay seller "Linearmotionbearings2008" Who sells TONS of these ballscrews there. I was skeptical when I was told they have a thread pitch of 5 turns per inch because if they are metric in diameter I would assume the pitch is metric as well. after cutting a few parts out I can say for sure they are NOT 5tpi... Is there a way to calculate the tpi on these ballscrews now that the machine is up and running? Or does any one know the real TPI on these ballscrews? Thanks for any help! I have attached a picture of my homemade CNC router I built that is cutting the undersized parts. -Jerome |
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#2
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| You need to set your motors SPI (steps per inch). If you are using Mach3, its a simple procedure. Below is a video that should help: |
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#3
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| clocksandblocks He probably ment 5mm, 5 turns per inch would be .200 per turn 5mm pitch would be .19685029 per turn enough to make your parts cut small But you can set it up as tulsaturbo has already said in the above post
__________________ Mactec54 |
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#5
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| Lay a ruler up to the ball screw and see how well the 5mm marks line up with the thread. If it looks good use mactec54's number of 0.19685029 inches per turn. Divide your steps per turn by the inches per turn and you get steps per inch. Assuming you are using 10x micro stepping drivers. 200 step per turn motors x 10 micro steps = 2000 steps per turn 2000 / 0.19685029 = 10160.005 steps per inch. |
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#6
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| clocksandblocks How did you do it to get the 5 turns per inch that you have now, if that is what you have entered, then just change it to 5.08000000002 & that will make it for 5mm pitch You most likely don't need all the zero's on the end
__________________ Mactec54 |
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#8
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#9
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| kawazuki 5mm is .1968503937 divide that x 1.00 will give you 5.08000000002 if you read the post you would of seen that I said he did not need all the zero's on the end so he would of put in 5.08, His screw is 16mm not 5/8 dia He had it set up for .200 this would make it cut undersize when it should of been for .196850
__________________ Mactec54 |
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#11
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Anyway why set the machine up with metric screws and talk in inches? Set it as metric - each unit is 1mm, the screw moves the object 5mm for every rotation? For every 1mm the screw rotates 0.2 of a turn or 10 steps. Use a G20 or G21 in code if you prefer working in imperial or native units, the converse obviously applies if the screw actually is imperial! Anyway - all the above rambling doesn't add up to 1.915" as opposed to 2" |
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