![]() | |
| Home Page | Mark Forums Read | Today's Posts | My Replies | Classifieds | Reviews | Photo Gallery | Web Links | Share Files | Advertise With Us | Ad List |
| |||||||
| Hobby Discussion Discuss other CNC-related Hobbies here. |
| This forum is sponsored by: |
![]() |
| | LinkBack | Thread Tools | Search this Thread | Display Modes |
|
#1
| |||
| |||
Hello, I have just about completed setting up my cheapo chinese cnc engraver but am confused about the 'instructions' the vendor sent me. I am asking here because the vendor is slow to respond and there is a language barrier. I attached the picture instructions... From this I am supposed to connect the 'select' terminals with some wire and then it should be good for 110v power on the ACin terminals? I am not familiar with this sort of stuff so I'm just learning as I go. I'll be amazed if I get this working without blowing something. roark |
|
#2
| |||
| |||
Looks right to me, and it's a pretty common method of selecting different voltage. However, if you aren't prepared to blow it up, I would wait for clarification from the vendor or have someone translate the documentation. |
|
#3
| |||
| |||
| Just make sure those 110V-select terminals are bridged and you should be fine. Also, when firing up the PSU for the first time. Don't have your precious electronics hooked up to it. If you blow it up, don't let it take something else with it to the afterlife. Not to scare you, it's just better to be safe in these situations. |
|
#4
| |||
| |||
| I'm in agreement with kineticstep and monstrum. Put a wire between the two select terminals and connect your AC pigtail cord to the AC IN terminals. The select jumper just reconfigures the input circuitry for the voltage you are operating the power supply on. It's equivalent to the red 110v/220v slide switches you see on PC power supplies and other modular power supplies. If you are looking at the DC output with a voltmeter when you turn it on, it may not go to the correct output voltage until there is a small load on the output. It depends on the regulator circuit design. CarveOne
__________________ CarveOne Resistance is not futile. It is voltage divided by current (R=V/I). |
![]() |
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
| Display Modes | |
| |
Similar Threads | ||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Need Help!- Chinese Power Supply connections | thudson | General Electronics Discussion | 2 | 03-19-2010 10:29 PM |
| Problem- controlling chinese laser power supply | dominicburke200 | Laser Engraving & Cutting Machines | 4 | 05-23-2009 12:45 PM |
| Power supply and an IM483 Wiring Question | sansbury | General Electronics Discussion | 0 | 08-06-2008 11:54 AM |
| micro ATX power supply wiring question | ericdwilso | General Electronics Discussion | 5 | 07-02-2007 10:15 AM |
| HELP! Simple wiring question! | WilliamD | General Electronics Discussion | 1 | 11-03-2006 12:20 PM |