HAAS SL20 and Bar loader question

[Spiderman]

I just started at my current job and I have a question regarding a HAAS SL20 program and the Servo Bar 300 loader.

The program is designed to "count" the number of pieces finished before loading a new bar. I came from CNC Swiss machines and programming bar feeders. I would like to know why I cannot restart this HAAS program at any process without the machine "thinking" that a new bar has been loaded. Below is the code:

0100
G28
G105
M97 P1 L5
/M00
M99
N1
G28
M36

T1010 (PART OFF)

T909 (SPOT DRILL)

and so on........until the PART OFF is up again to part off the finish piece.

Thanks in advance!

[gizmo_454]

We have both an SL-10 with the Servo 300 bar loader, and a Citizen swiss screw machine. 2 completely different animals. To make a long story short, I write my SL-10 programs like this, (SL-20 should work the same):

O100
(CUSTOMER & PART NUMBER)

G54 G50 Snnnn

(FACE AND TURN OD)
G00 G28 U0 W0
G97 S1500 M03
T101
G00 X1.625 Z0 M08
G96 S330
G01 X-0.06 F0.004
G00 Z0.1
G00 G42 X1.25 Z0.1
G01 Z0
G01 X1.4 R-0.03
G01 Z-1.
G01 X1.5 K-0.005
G01 Z-1.25
G01 X1.625
G00 G40 X1.75 M09

(CUT OFF)
G97 S1000 M03
G00 G28 U0 W0
T505
G00 X1.625 Z-1.25 M08
G01 X1.45 F0.0036
G00 X1.55
G01 X1.5 Z-1.2
G01 Z-1.25 R-0.018
G01 X0.125 M36
G01 X-0.01 F0.0012
G00 X1.625 M09

G00 G28 U0 W0


G105 In.nnn Jn.nnn Kn.nnn
M37

/M99
M30

Running with Block Delete off will make parts continuously and load a new bar when the machine runs out. Turning on Block Delete will be the same as running in Single Part mode on the swiss.

If you have macros enabled on the machine, you can setup a macro to cut the end of the new bar off before starting to make parts. If macros are not enabled, just make the initial push long enough for the machine to cut off the end of the bar when the program reaches the cut off process in the program. I have done this with success many times. You just have to be careful if your part has a through hole and you are sinking a carbide drill in the end of the bar without a spot.

I am not sure why you would count the parts using a subroutine loop. The machine knows how much material is left and whether there is enough there to make another part or not. By writing your program similar to the program above, you can then start at any tool change in the program and finish making the part. Want to fix something? No problem.

After the cut off process, the machine will push the bar out for the next part. Depending on whether block delete is on or not, the machine will either stop after the barloader or continue making parts.

I hope I did not make you any more confused. Please feel free to PM me if you have any questions.

Mike

[Spiderman]

gizmo_454,

Thank you for your help. The initial bar count was programmed to get the parts up and running. I came in a few weeks later and I am just figuring out what these parts do and how I can make this more efficient. I will research the "I", "J", and "K" for the subprogram. The bar being loaded is 42".Below is the program (in most of its entirety):

Thank you!

%
O10006 (Part Name)
G28
G105
M97 P1 L4
/ M00
M99
N1
G28
M36

M37
T1010 (PART-OFF)
M88
G50 S1000
G97 S500 M03
G57 G00 Z-0.03
G96 S180
X1.28
G01 X1.26 F0.0018
X1.19 Z0 F0.003
G01 X-0.05 F0.0018
W0.02
G00 Z4.
M89
G28 U0
M01

T909 (1/2 SPOT DRILL)
G50 S2100
G97 S2000 M03
G57 G00 Z0.5 M88
G98
X0.
Z0.1
G83 Z-0.4 Q0.16 R0.1 F6.
G80 G00 Z2. M89
G28 U0
M01

T808 (1/2 CENTER DRILL)
G50 S1600
G97 S1500 M03
G98
G57 G00 Z0.5 M88
X0.
Z0.1
G82 Z-0.425 P0.8 R0.1 F6.
G80 G00 Z0.5 M89
G28 U0
G28 W0
M05
G99
M36
M01

G105
M37
M21
M01
T707 (GROOVE-TOOL)
G50 S2500
G97 S2000 M03
M88
G110 G00 Z-2.673
G96 S700
X1.3
G01 X1.185 F0.002
G04 P0.1
G00 X1.3
Z-5.937
X1.26
G01 X1.185 F0.002
G04 P0.1
G00 X1.26
G00 X6. Z0 M89
G28 U0
M01

T404 (KNURLER)
G50 S600
G97 S450 M03
M88
G110 G00 X6.4 Z-0.788
X1.26
G01 X1.142 F0.005
G04 P2.5
G00 X1.5
Z-2.123
X1.26
G01 X1.154 F0.009
G04 P2.5
G00 X1.5
Z-6.803
X1.26
G01 X1.166 F0.009
G04 P2.5
G00 X1.5
Z-8.138
X1.26
G01 X1.174 F0.009
G04 P2.5
G00 X1.5 M89
G28
M05
M19 P180

M14
M01
T606 (LIVE TOOL .266 DRILL)
G98
G110 G00 Z-2.87
M88
M133 P2800
G04 P4.
X1.35
G01 X0.2 F9.
G00 X1.5
G01 X0.3 F50.
G01 X-0.1 F5.
G00 X1.5
G01 X-0.025 F50.
G01 X-0.225 F5.
G00 X1.5
Z-5.661
G01 X0.2 F9.
G00 X1.5
G01 X0.3 F50.
G01 X-0.1 F5.
G00 X1.5
G01 X-0.025 F50.
G01 X-0.225 F5.
G00 X1.5
M89
M135
G28 U0
G99
M15
M01

T202 (5/16-18 TAP)
G110 G00 Z-2.87
X1.6
S235
M19 P180
M14
M88
G195 X-0.415 F0.055555
G00 Z-5.661
S235
G195 X-0.415 F0.055555
M89
G28 U0
M15
M01

T1010 (PART-OFF)
M36
G50 S1000
G97 S400 M03
M88
G110 G00 Z-8.656 X1.28
G96 S225
G01 X1.15 F0.002
G00 X1.3
W0.03
G01 X1.25
W-0.03 U-0.06
X-0.03
G00 X1.5 M89
G28
M37
M01
M99
%

We have both an SL-10 with the Servo 300 bar loader, and a Citizen swiss screw machine. 2 completely different animals. To make a long story short, I write my SL-10 programs like this, (SL-20 should work the same):

O100
(CUSTOMER & PART NUMBER)

G54 G50 Snnnn

(FACE AND TURN OD)
G00 G28 U0 W0
G97 S1500 M03
T101
G00 X1.625 Z0 M08
G96 S330
G01 X-0.06 F0.004
G00 Z0.1
G00 G42 X1.25 Z0.1
G01 Z0
G01 X1.4 R-0.03
G01 Z-1.
G01 X1.5 K-0.005
G01 Z-1.25
G01 X1.625
G00 G40 X1.75 M09

(CUT OFF)
G97 S1000 M03
G00 G28 U0 W0
T505
G00 X1.625 Z-1.25 M08
G01 X1.45 F0.0036
G00 X1.55
G01 X1.5 Z-1.2
G01 Z-1.25 R-0.018
G01 X0.125 M36
G01 X-0.01 F0.0012
G00 X1.625 M09

G00 G28 U0 W0


G105 In.nnn Jn.nnn Kn.nnn
M37

/M99
M30

Running with Block Delete off will make parts continuously and load a new bar when the machine runs out. Turning on Block Delete will be the same as running in Single Part mode on the swiss.

If you have macros enabled on the machine, you can setup a macro to cut the end of the new bar off before starting to make parts. If macros are not enabled, just make the initial push long enough for the machine to cut off the end of the bar when the program reaches the cut off process in the program. I have done this with success many times. You just have to be careful if your part has a through hole and you are sinking a carbide drill in the end of the bar without a spot.

I am not sure why you would count the parts using a subroutine loop. The machine knows how much material is left and whether there is enough there to make another part or not. By writing your program similar to the program above, you can then start at any tool change in the program and finish making the part. Want to fix something? No problem.

After the cut off process, the machine will push the bar out for the next part. Depending on whether block delete is on or not, the machine will either stop after the barloader or continue making parts.

I hope I did not make you any more confused. Please feel free to PM me if you have any questions.

Mike

[gizmo_454]

The "I", "J", and "K" for the bar loader are as follows:

I = Initial push (new bar)

J = Part Length+Cutoff+Facing Length

K = Minimum Clamping Length

Running the program as I have noted above, the bar length will not be as important. You can run from the max length the bar loader/machine combo allows down to a minimum of 12". The machine won't care since it measures every bar it loads automatically. The only place I see it might be good to cut the bars to an accurate length every time is when you are trying to minimize the length of the bar end (remnant).

Good luck to you!

Mike

[Spiderman]

Mike,

Thanks again. I found the information this morning in the bar loader addendum which I did not know we had that was behind the HAAS SL20 Manual.

The information we have in our Current Command page for the part length, bar length, and the initial push should suffice, correct?

If need be, I can send you a PM to end this thread.

Thanks.

William

The "I", "J", and "K" for the bar loader are as follows:

I = Initial push (new bar)

J = Part Length+Cutoff+Facing Length

K = Minimum Clamping Length

Running the program as I have noted above, the bar length will not be as important. You can run from the max length the bar loader/machine combo allows down to a minimum of 12". The machine won't care since it measures every bar it loads automatically. The only place I see it might be good to cut the bars to an accurate length every time is when you are trying to minimize the length of the bar end (remnant).

Good luck to you!

Mike

[gizmo_454]

Mike,

...The information we have in our Current Command page for the part length, bar length, and the initial push should suffice, correct?

If need be, I can send you a PM to end this thread.

Thanks.

William

William,

That is correct. I tend to write it in my programs so that the next time I want to make the part, I don't have to enter it in the Current Command page. One less step to the setup. But that is personal preference.

Keep up the good fight!

Mike