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Thread: Please HELP! Haas sl-30 od grooving math help

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    Please HELP! Haas sl-30 od grooving math help

    Having trouble with the math on this od groove; unsure how to calculate 22 and 33 degrees of center of groove; also trying to use canned cycle with tnc I'm guessing would be the easiest??

    http://s1233.photobucket.com/albums/ff389/haaswork/?action=view&current=460b7fa4.jpg&evt=user_media_share[/IMG]


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    Option 1: Using two offsets and theoretical cutting points (3 and 4), groove everything in one direction, then come back and groove in the other.

    Option 2: Touch off a 20' tool to the center of your nose radius and program the entire profile offset the amount of the tool nose radius.

    With either option, DO NOT leave stock on the Z axis in your G71 line, as this will cause the tool to cut into the opposite surface on this tight of a groove.

    There a likely many other options, but these are the two I personally would use.


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    Registered CNCRim's Avatar
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    the second option like ad64075 said is best bet.

    Post the rest of dimension ..... I/some of us on here can calculation for you.
    The best way to learn is trial error.


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    Only dimensions I have are; depth of groove at x3.125 on a radius of .125 centered 2.313 back 33 deg angle towards front of part rounding out on a r.063 to x3.625; 22 deg toward rear of part radius out on r.063 to x4.125:; jpeg link attached shows print

    http://s1233.photobucket.com/albums/ff389/haaswork/?action=view&current=460b7fa4.jpg&evt=user_media_share[/IMG]


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    Registered CNCRim's Avatar
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    On the print you show us the information is missing is the smallest diameter and the location where 120deg angle start. without start location of 120deg I assume x3.625 with .063full rad then rotate 120deg ..... So that small diameter is 2.9694.


    OK I guess this is lathe work, the code will be like

    G0 X2.9694
    G1 Z-1.8229 (this number is back track from the 120deg, as the designer before make any part)
    X3.5620Z-1.9940 (****this Z number change if start location is off*******)
    G3X3.6250Z-2.0485R.063(From here on the infor is clear so I know it's right)
    X3.5676Z-2.1014R.063
    G1X3.2388Z-2.2081
    G2X3.2813Z-2.42889R.125
    G1X4.0462Z-2.5834
    G3X 4.125-2.6418R.063
    The best way to learn is trial error.


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    I keep alarming out on the line of x4.062 z-2.5834; w/ a invalid R in G02/G03


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    Registered KenFoulks's Avatar
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    Add a G01 to the beginning of that line.
    Thanks,
    Ken Foulks


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    Registered CNCRim's Avatar
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    On the last line I missed "Z". Did you have that in the program?
    The best way to learn is trial error.


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    Yes, I added the z; the G1 fixed it. Tremendous help, thankyou. One more thing though, would you mind explaining to me how you did the calculations to get the proper dimensions? The 22 &33' angles without any other dimensions throws me off...


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    I will try my best and short, because I hate to explain without pictures attach and plain words. OK, you know the dimension is 2.313, 2.615 is the deep of groove, the radius .125. Keep in mind the angle change the radius and center of the radius will never change. So 2.615+(.125x2)= 2.825 then now let trig out 22deg Sin 22 *.125(rad) = .xxxx . Take that xxx number times 2 because that's is need to diameter then subtract 2.825. For other Z dimension is Cos 22 *.125(rad) = xxxx. then take that xxxx number add to 2.313.

    just repeat the process for rest of dimension.

    PS: try to do the SIMPLE one first like one angle tangent to radius before to complex one.
    The best way to learn is trial error.


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    How, or where are you coming up with the 2.615 dimension? Is it X or z dimension?


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    Registered CNCRim's Avatar
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    My mistake!!! 2.615 should be 3.375

    The center X location of .125R should be 3.375(3.125+.125*2)

    FYI, go on Haas website and look for Handbook manual and download it. It has quite a few exercises will teach you how to do similar problem. Check it out.
    The best way to learn is trial error.


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