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#1
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Say I need 20 ohms and I only have 10 ohm resistors, by connecting 2) 10's end to end what is the effect? Is it going to multiply the resistance by 10 ? and also if I connect them parallel does it just increase the wattage? |
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#2
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| Resistors in series add resistance, so two 10s will make a 20. Two *equal* resistors in parallel halve the resistance, so two 10s will make a 5 at double the power handling. robotic regards, Tom = = = = = Times are fun when you're having flies. Kermit The Frog |
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#3
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| If two resistors (R1, R2) in series, the total resistance global is the sum of the resistances: R'=R2+R1 If two resistors (R1, R2) in parallel, the total resistance is R'=(R1*R2)/(R1+R2). As Toymaker said, if the two resistors are equal (value R, for example) and you wire it in parallel then the final resistance is R'=(R*R)/(2R)=R/2 Fer |
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#5
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| OK so I have only 10 ohm resisters in 50 and 25 watt, in order to get 16.5 ohms at 122 watts min. is this diagram correct? 50 - 50 - 25 parallel 50 - 50 - 25 50 - 50 - 25 50 - 50 - 25 50 - 50 - 25 series = 16.5 ohms at 125 watts or is it 625 watts 50-50 parallel 50-50 50-50 series does this =15 ohms @ 300 watts
__________________ ...He who makes no mistakes makes nothing! ... Tom Last edited by tpworks; 04-26-2004 at 08:13 PM. |
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#6
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| Take // as the simbol of parallel, and + as the symbol of series, so: 10//10=5 10//10//10//10=2.5 10//10//10//10//10//10//10//10=1.25 10+(10//10)+(10//10//10//10//10//10//10//10)=10+5+1.25=16.25 ohm Do not worry about the 0.25 of difference, the resistors usually have a 5% or 10% tolerance. With the array of 11 (eleven!) resistors if you use 25W you have 275 Watts. But with the size of the power resistors this assembly will look like a eiffel tower and can be used to warm your bedroom . Honeslty, I think you must consider buying new resistors or some other approach Fer |
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#7
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| the reason I am using these figures is I recently purchased a large amount of these resistors on Ebay. Here is the description. Large Lot of Misc Dale Resistors Large lot of Dale resistors inclludes (37) RH-50, 50 watt, 10 ohm, 1% resistors and (94) RH-25, 25 watt, 10 ohm, 1% resistors. Also included are (10) IRC SXAL50, 10 ohm, 5% resistors. 10//10+10//10+10//10=15ohm 2)25w 2)25w 2)25w = 150w will this work using 6 per motor winding
__________________ ...He who makes no mistakes makes nothing! ... Tom Last edited by tpworks; 04-26-2004 at 09:54 PM. |
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#9
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| I would go option 1, 6 resistors per coil. Get a big heatsink. Very big. You will be dumping 250 watts per motor into it. That is a whack of heat. What board will you use? Eric
__________________ I wish it wouldn't crash. |
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