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#1
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Hey people. There is something rolling around in my head since a few days now, because making a job of reverse engineering on a Ricoh stepper driver pcb, and found that: 1 of the connectors of the board needs 24 volts for motor powering. 1 connector it is 100% sure for ground. 1 of the connectors goes to a PNP transistor and also motor powering and that’s my question: If found a PNP transistor on the board, obviously together at the side with 24v, should I suspect that I need negative voltage on that? Should be of the same current rating than 24v? The device is 2SB1031 and here is the datasheet (The symbol –, negative, is everywhere): 2SB1031 pdf, 2SB1031 description, 2SB1031 datasheets, 2SB1031 view ::: ALLDATASHEET ::: Please be advice that im not talking about ground connections here. Please Help!!! |
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#3
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| On the 24 volt connector it is a rectifier diode. both, the rectifier and the PNP transistor end up at going to motor power mosfets |
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#4
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| That link goes to the 2SD1435 ? An PNP does require the Base voltage to be -ve relative to the Emitter, to turn on. This does not mean that the base voltage has to be -ve wrt ground/0-volts. The datasheet probably refers to relative voltages, not absolute. It sounds like the PNP is being used as a gate driver for N-type mosfet. It's another (cheaper) way to switching the mosfet on faster. It is more advisable to use a mosfet driver chip for this purpose. The diode could either be a blocking diode (preventing voltage going back into the circuit causing damage) or a freewheeling diode (connected to the drain) to suppress the power spikes from the motor. If connected to the gate, it's probably a clamping zener diode as mosfet gates are usually limited to 20V max. Google 'driving mosfets'.. there are plently app-notes on this. Last edited by vanjast; 12-15-2010 at 05:55 PM. |
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