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#1
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Hi Folks, I am trying to solve a basic electrical problem but unfortunately my disability (ME/CFS) is acting up tonight and I am feeling decidedly 'brain fogged' and confused . Can someone please check my 'thinking' to make sure I am heading in the right direction? The problem I face is that I promised to make a number of 'trophies' for the annual charity kite festival for the kite club I belong to. The festival is the weekend after next and I need to get my system up and running ASAP if I am going to get them made. Unfortunately my original motors/board were not fast enough for my needs and I have upgraded my system to a Hobby CNC board, larger motors and a bigger power supply. I have the board built and I am awaiting delivery of the transformer so that I can build a larger power supply. In the meantime I am trying to get everything else sorted and the wiring figured out so that when the transformer arrives I can simply solder everything together.Now, my original idea was to have an e-stop button controlling the coils of two relays, the switch would be wired NC so that it 'pulls' the contacts 'in' when in the 'up' position and when the e-stop is pressed the relays would drop out thereby killing the power. One relay would switch the 110VAC line going to the router motor and the other would switch the DC voltage going to the board and therefore the stepper motors. With the increase in DC supply voltage I am now confused as to the best method of reducing the voltage so that I can 'feed' the coils of the relays. The information I found on the net for the relays in question (Potter & Brumfield type KRP11DG) says the coils are rated at 24VDC, with a resistance of 472 Ohms and a nominal coil current of 51 mA. My transformer is expected to put out 25VAC at 10A so by the time it has been through the bridge rectifier and smoothing cap I will be looking at 35.35VDC available to the board. In order to obtain 24VDC to feed to the relay coils can I simply insert a resistor into the feed line to the coils (if so what size/wattage) or do I need to build a voltage divider using two resistors with a 'tap' point between the two (and if so what size/wattage)? I am rather embarrassed that I can't figure this out myself as I am a qualified ham radio operator and used to be able to do this stuff with no problems before being struck down with this 'damn disease'!As a side note, my new board has the ability to take an e-stop signal and feed it back to my controller (Turbo CNC). My previous board did not which is why I was killing the DC voltage to the board to stop the stepper motors in an emergency. I was hoping that TCNC would see the loss of signal on the limit switch line as a 'hit limit' and stop the program otherwise the program would continue to run even though everything else had stopped. Does anyone have any ideas on how I can supply a signal to the board with the set up described above bearing in mind the e-stop circuit is likely to be on 24VDC and I am guessing the board/TCNC is looking for a change in state on a 5VDC signal. If I can solve these problems before my transformer arrives on Friday I might be able to meet the deadline although we do have a contingency plan to produce 'certificates' if I can't get the trophies made in time. Any help greatfully appreciated. Larry |
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#2
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| Try 200ohm 1W. But you may check the relay specs as they do not require 24.00V but rather 24V +- something. I would not be surprised if 35V is OK. Or 17.5V as you get if wiring them in series. 17.5V will probably justmake them engage a fraction of a second slower, but in your case it is the release time that should be fast anyway. And that will not be slowed down. For your feedback to the PC use a photocoupler. Then your PC will be protected from current loops, voltage spikes and other nasty things in your power electronics. Use 1800 ohm to limit the current from 35V into the diode of your optocoupler. |
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#3
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| One other point: using a switch for e-stop is not a good idea, it's better to use a Start and a Stop button. What I did was use a relay with a 220V coil and four contacts (only used three). The Start button is N.O. and the Stop N.C. and they are wired in series to the coil. One set of contacts is wired parallel to the Start button. So, if I press the Start button current flows through it, the stop button and the coil so the relay is armed. When I release the button the relay stays armed because the parallel contact acts as if I was still holding the button. If I press the Stop button I will open the circuit and the relay will reset. The same will happen in a power failure, and this is the advantage against using a switch: say you're using a switch and there's a black out. You wait for the power to come back up but get bored and decide to call it a day. You try to remove the workpiece or tool and suddently the power comes back up. Ooops!!! If you have the setup I mention nothing will happen unless you press Start again. The second condact is used to notify the PC that the e-stop was pressed. It doesn't make any sense now since the PC wouldn't be open in a power failure but 1) You might be using a UPS 2) The power failure might be in the machine (e.g. a wire was disconnected) The third is of course the power output which is connected to another relay controlled by the PC (with the M3 command) |
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#4
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| For an ESTOP switch I recommend a BIG RED BUTTON with normally closed contacts. There are special switches made for this. Some are pull to reset; others are turn to reset. www.mcmaster.com has five pages of these things. Allied Electronics also carries them. I bought one in an oil tight box for around $45.00. If you buy just the switch, you can save some money. Ken
__________________ Kenneth Lerman 55 Main Street Newtown, CT 06470 |
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#5
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| I agree with Einar that the relays can in all probability take the higher voltage, this would cause a 76ma current which they should be able to handle, also the 'latched' on/off/e-stop circuit is a good idea. Is there an enable input on the amplifiers? as this is sometimes a really good way to disable the motors immediately, if you drop the AC power out to the amps only, then the residual charge in the DC supply caps can in some cases cause the motors to keep on moving until the charge has decayed. Al.
__________________ CNC, Mechatronics Integration and Machine Design. “Logic will get you from A to B. Imagination will take you everywhere.” Albert E. |
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#6
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I will look into this option, thanks for your help. Larry |
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#7
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Larry |
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#8
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Larry |
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#9
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Larry |
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#10
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| Current limit the 35 VDC to the relay coil to the power rating of the coil and you should be okay. You want to limit the current to under 50 ma....probably somewhere around 40 ma. If you don't want to experiment then add a voltage divider for each coil. |
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#11
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Believe me I have done it, relays that switch high current DC are fitted with Arc-Blow-out magnets for this reason.Al
__________________ CNC, Mechatronics Integration and Machine Design. “Logic will get you from A to B. Imagination will take you everywhere.” Albert E. |
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#12
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