
02-10-2009, 12:36 PM
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| | | Join Date: Jul 2007 Location: Sweden
Posts: 886
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Hi,
I don't have any G320's so I hope I'm not too far off here but here's how I see it.
Originally Posted by rbcmetalwork For any given G320:
Are three things attached to terminal 6 of the G320? The wire from the encoder negative, the wire from the 5VDC power supply ground and one end of the 470 ohm resistor? |
Yes, that is correct. The resistor is there to "fool" the drive thinking it is supplying current to an encoder. I believe it's needed for the internal voltage regulator to work properly. The ground for the encoder and ground from the powersupply gives the encoder and G320 a common reference for the A and B signals.
Originally Posted by rbcmetalwork Are three things attached to terminal 7 of the G320? The wire from the encoder positive, the wire from the 5VDC power supply positive and the other end of the 470 ohm resistor? |
NO. Only the other end of the 470 ohm resistor. This terminal is the +5V "output" so you shouldn't connect the external +5V powersupply to it. Connect the external +5V to your encoders positive wire only.
Originally Posted by rbcmetalwork Can a single 5VDC power supply, with adequate current, be used for powering all three encoders (One output going to three places)? |
Yes, that shouldn't be any problem. Wire the +5V from you external powersupply to the postive lead of all three encoders but not to any connection on any of the drives. What wattage should the 470 ohm resistor be? |
Since the voltage across the 470ohm resistor is 5V the current thru it is ~11mA so the power is developed in it is ~0.05W. A 1/4W or 1/8W resistor is more than enough.
HTH
/Henrik. |