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#1
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I'm pretty new at this and I need to circular interpolate an 11/16s diameter boss on a small eccentric shaft. It will be .250 high when it's done. I have gotten it to graph on a haas TM1, and it does run, but it doesn't look like it is doing what I need it to do. The teacher of this class isn't much help, and I need to finish this today. If anyone can get back to me asap I'd really appreciate it. I really only need one block of it to be right, then I can make the rest the same just with a different depth for it to feed down. Go easy on me guys.. lol % O04401 (part 44 side 1) T1 M06 (LOAD ENDMILL) G90 G54 G41 (ABS OFFSET CC ON LEFT) G43 H01 (TOOL LENGTH TOOL#1) M03 S300 (SPINDLE ON 300 RPM) G00 X0 Y0 (RAPID TO ORIGIN) G00 X2.0 Y0 (RAPID TO PT#1) G00 Z0.1 (RAPID TO R-PLANE) M08 (COOLANT ON) G01 z-.050 D01 f4.0 (feed down .050) G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part) G01 z-.1 D01 f4.0 (feed down .1) G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part) G01 z-.15 D01 f4.0 (feed down .15") G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part) G01 z-.2 D01 f4.0 (feed down .2) G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part) G01 z-.25 D01 f4.0 (feed down 1/4") G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part) G00 Z1 m09 G40 Z0 M05 M30 % |
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#5
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| I wasn't asking for anyone to make me a program I was just asking if anyone saw anything wrong with the one I have. The diameter of the endmill is 1.165, it is a 6 flute endmill. I want the center of the circle to be the origin. Thanks. |
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#6
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| "I" should be negative (G02 I-.3438 not unless your control takes absolute I and J0). Move G41 to (move over to edge of circle) block Add G40 to G01 x2.0 (clear part) block .....Try that first Last edited by guru; 02-03-2010 at 09:16 AM. Reason: . |
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#7
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| "G01 z-.050 D01 f4.0 (feed down .050) G01 x.3438 f4.0 (move over to edge of circle) G02 I.3438 J0.0 (circle clockwise) G01 x2.0 (clear part)" I think after a quick look you need to have a I-.3438 in your G02 line I believe the rule is "Distance and direction from the start of the arc to the center of rotation." Comment-- I see Guru posted while I was writing this. I agree with his answer Last edited by JWK42; 02-03-2010 at 09:20 AM. Reason: comment |
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#8
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| capitalcrew This program will rough cut all the way done in .06 steps & then do a clean up pass around the part no D01 needed in the program, just save the program & put it in the machine, it has the same program number as you had plus same speed & feed There is no G40/G41 if you want need to have cutter comp it will have to be added to the last operation
__________________ Mactec54 Last edited by mactec54; 02-03-2010 at 10:00 AM. |
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#9
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#10
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| I figured out the cutter comp and d01 stuff, and changed it. I tried making the I value a negative and it didn't graph on the machine. I'm using a Haas TM1, I'm guessing the controller is the panel that has all of the controls on it haha. I'm not sure what it is, it came with the machine I believe. |
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#12
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| The problem I see with your initial program is that you are calling D01, but not calling it on a comp initation line G41/G42. Or rather you are not calling any compensation mode at all, so having the D01 in there does absolutely nothing |
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