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#4
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| The math isn't pretty, but here's a link to the answer: http://mathforum.org/library/drmath/view/53179.html Any good cad program can solve this problem graphically. Given: 2 points (X1,Y1) & (X2,Y2) on a circle of radius R. Draw a circle of radius R centered at (X1,Y1) Draw another circle of radius R centered at (X2,Y2) The points of intersection of these circles are the possible centers. (XC,YC) |
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#5
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| To calculate circle center isn't very easy... I made a little software to 'convert' a Gcode file to DXF file. Just import DXF in any CAD software and pick circle centers or any other informations you need... Look here Hope this can help |
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#8
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Point 1 x coord = A POINT 1 Y COORD = B POINT 2 X COORD = D POINT 2 Y COORD = E CIRCLE RADIUS = F WHEN THE CIRCLE IS LEFT OF THE LINE FROM POINT P1 TO POINT P2 G=-1 C=F H=D-A I=E-B J=√(H * H + I * I) K=ACS(H/J) IF 0>I THEN K = -K ACS((C*C+J*J-F*F)/2/C/J) M=A+C*COS(K+G*L) N=B+C*SIN(K+G*L) CIRCLE X COORD = M+ SGN M * .005 CIRCLE Y COORD = N+ SGN N *.005 |
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#11
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Trig Kalculator from Kentech Inc. will easily perform this calc and many others ... $95. Info and demo at www.KentechInc.com |
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