N20 G01 X94.625 Y125.000 F320.000
N21 G03 X85.000 Y134.625 R9.625 F320.000
So I get the start and end points on the arc, the radius and the direction.
Unless the separation happens to be 2r there are two possible solutions, two possible locations for the centre of the arc.
Find one center, mirror it across the two points and get another possible center.
Perhaps I missing something, not understanding
Terminally frustrating, have 3 axis mill, have g-codes, need to write an interface, not an Ixxx or Jxxx in sight, stuck, HELP![]()


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