Need Help!- Lathe Circular Interpolation C axis

[jorgehrr]

Nakamura TW10 Fanuc 18T
Trying to save set up time. Very low volume job.
One of the operation require a .625 rough hole. I'll like to use a .5 dia. End mill already in the machine.
How do I interpolate to make a .5 end mill cut a .625 diameter hole.
This is how I'm planning on doing it:
Z0.0 is face of material.
After I engage C axis....
G and orientation codes...

G0X.0625Z.1
G1Z-.250
C360.F15. or H360.F15.
I'm trying to make C axis rotate 360 degrees to increase the hole diameter.
Please advice if this is a good way to do this.
Can I use X and Y axis like in a machine center instead??? G2 or G3 from the center of the hole??

Any input will be appreciate.

Regards.
Jorge.

[dcoupar]

I think the H360. should work. I believe your feedrate will be in degrees per minute, so F15. will take about 24 minutes to make one rev.

[jorgehrr]

So much for a set up reduction. LOL
Thanks for ur replay.
I have a small macro that will take care of the feed rate.

O9005*
#[#18] = #2/[[3.1416 * 2 * #7] * #2 /360] / #9*
M99

Again. Thank u very much.

[sinha_nsit]

Originally Posted by jorgehrr ... Can I use X and Y axis like in a machine center instead??? G2 or G3 from the center of the hole?? ...

Not possible, though I am not very sure.

[steveptrs]

Ok I have a very similar issue. I am looking for a formula to calculate feedrate in degrees per minute. Does anyone have anything?

[dcoupar]

Originally Posted by steveptrs Ok I have a very similar issue. I am looking for a formula to calculate feedrate in degrees per minute. Does anyone have anything?

This might help...

[g-codeguy]

How long could it possibly take to mount a 5/8 inch drill?

[g-codeguy]

Originally Posted by dcoupar This might help...

Thanks for the link. I have a couple old jobs I would like to try using these formulas on. Just to see how close my guesstimates are.