Hi Beppe,
1MHz / 50 revs/sec = 20000 quadrature counts/rev maximum
Or 5000 lines or cycles/rev
HTH
Regards
Question for Tom
I am looking for a lathe retrofit and the question is:
considering the max spindle velocity as 3000 Rpm, what is the right spindle encoder steps/revolution needed for not to exceed the Kflop input bandwidth
Beppe
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Hi Beppe,
1MHz / 50 revs/sec = 20000 quadrature counts/rev maximum
Or 5000 lines or cycles/rev
HTH
Regards
Regards
TK http://dynomotion.com
thanks Tom