CNCzone.com-The Largest Machinist Community on the net!



Home Page Mark Forums Read Today's Posts My Replies Classifieds Reviews Photo Gallery Web Links Share Files Advertise With Us Ad List
Go Back   CNCzone.com-The Largest Machinist Community on the net! > MetalWorking > Bending, Forging,Extrusion...


Bending, Forging,Extrusion... Discuss Bending, Forging, Extrusion technique's here.


Reply
 
LinkBack Thread Tools Search this Thread Display Modes
  #1   Ban this user!
Old 03-23-2007, 02:02 PM
FishGuy876's Avatar  
Join Date: Mar 2007
Location: USA
Age: 35
Posts: 5
FishGuy876 is on a distinguished road
Post CNC Bender Mathematics Questions

I hope this is the right forum to post in =) If not, I can always move the post.

I am a programmer with a company that produces semi-rigid circular cable parts. We currently employ the use of 5 CNC benders that use XYZ tables to bend the cable into the shapes we need for our customers designs. Some examples of what we build can be found on http://www.rosenbergerna.com We use cable that ranges in size from 0.070 to 5 inches thick, some are solid copper / aluminium, some are more flexible.

The benders that we currently use are MS-DOS-based, using Parker AT6400 controller cards. Two of the benders are older than that, and contain a huge controller device hooked up via serial port that uses Parker / DigiPlan controllers and relays. Some pics of this ancient beast can be seen at http://www.f1-software.com/gallery/t...s.php?album=17

One of the projects that I am working on here is to work on some new software to bring these machines up to a more modern perspective. I have purchased the ACR1505 controller card from PArker along with the SDK's etc. and will be developing a new bending tool in c++ to work with these, plus additional machines.

Problem I am running into is with the mathematics regarding the cable bending process. When a design is submitted to us, a customer typically sends us an X, Y,Z table, which is used to compute the cable in 3d. All points except the first 2 are virtual, meaning they may expand out until they meet, then the arc of the bend sits on either side of the intersection. What I am looking for is links or reference material to how to manually compute this information so I can teach my program how to correctly compute the segment lengths etc. from this data. Any help at all would be appreciated as I have been trying to find it for quite some time.

If you require any more information, please let me know and I will be glad to provide it.

Thanks

Andy Kellett
Tweet this Post!Share on Facebook
Reply With Quote

  #2  
Old 03-23-2007, 04:43 PM
Gold Member
 
Join Date: Dec 2004
Location: Newtown, CT, USA
Age: 67
Posts: 511
lerman is on a distinguished road
I did some coding for a similar problem about 40 years ago, for bending hydraulic lines in aircraft. I believe that the first and last points were actual coordinates, while the middle points were "virtual", to use your term.

I assume that the problem you wish to solve is where to begin each bend given the geometry, that is, the radius of the bend and the bend angle. If an angle of zero represents no bend, then the bend must start a distance equal to the radius of the bend times the tangent of the bend angle before the next point.

The bender I worked on required three items: (1) the distance to feed the tubing before the next bend, (2) an amount to rotate the tubing around its axis, and (3), the bend angle. Given the table of coordinates in three space, the program computed the series of values to use for the machine. It also required the bend radius, which was constant for a given product.

Ken
__________________
Kenneth Lerman
55 Main Street
Newtown, CT 06470
Tweet this Post!Share on Facebook
Reply With Quote

  #3   Ban this user!
Old 03-26-2007, 06:57 AM
FishGuy876's Avatar  
Join Date: Mar 2007
Location: USA
Age: 35
Posts: 5
FishGuy876 is on a distinguished road
Talking

Yes, this is exactly the type of work it is doing. I apologize my first post wasn't too descriptive there =)

It works by retracting the axis back far enough to insert the entire length of the cable, then feed it through, rotate it and bend it at the angles needed. The whole process is done through a table of X, Y and Z coordinates, and just like you say, the only two real sets of coordinates are the first and last. The others extend out into space to connect the straights in order to compute the arc.

The way that our DOS benders do it is it uses a file format derived from HP called a Bend file (BND format) which is exported from the CAD program. This places the computations for set length, degree of bend etc. right in the file. We would like to compute this data on the fly using only the XYZ table, and not have to rely on using a CAD program.

Our current DOS programs were written in the early 80's and as such, no source is available for me to port to C++. Any help on where I should start to look is greatly appreciated =)

Andy 'Fish-Guy' Kellett
Tweet this Post!Share on Facebook
Reply With Quote

  #4  
Old 03-26-2007, 11:35 AM
Gold Member
 
Join Date: Dec 2004
Location: Newtown, CT, USA
Age: 67
Posts: 511
lerman is on a distinguished road
This is the type of thing I used to do for a living (before I semi-retired). I would start by producing a functional spec. What are the inputs? What are the outputs? What are the algorithms to get from one to another?

I assume that the inputs are the X, Y, Z tables. The outputs are the signals to drive the hardware. The machine geometry and interfaces will need to be specified with a simple model that can be easily understood by the implementor.

You will need to have or acquire certain skills to do this job. The mathematics is really pretty simple. If you can't handle the trig/geometry yourself, I would suggest finding a consultant to help. A local college might have someone who can help you at a reasonable rate.

I would guess that by the time you are done, it would cost you a few tens of thousands of dollars for the entire job (software only). It's would be a fun job. In some ways, I'm sorry I'm not really available to quote on it.

Ken
__________________
Kenneth Lerman
55 Main Street
Newtown, CT 06470
Tweet this Post!Share on Facebook
Reply With Quote

  #5   Ban this user!
Old 06-06-2007, 11:24 AM
 
Join Date: Jun 2007
Location: UK
Posts: 12
mikek10 is on a distinguished road
You can find xyz to ybc (aka lra) conversion programs on the internet by many tube bending machine manufacturers

If you still can't find one contact me
Tweet this Post!Share on Facebook
Reply With Quote

Sponsored Links
Reply




Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
good pipe bender MBG Bending, Forging,Extrusion... 45 01-25-2007 11:01 PM
Programming / Setup help for bender. doanwannapickle Mach Software (ArtSoft software) 3 11-17-2006 03:48 PM
Rebuilding a Grizzly Bender... InspirationTool Bending, Forging,Extrusion... 2 06-03-2006 07:09 AM
Building a CNC bender packwalkin Bending, Forging,Extrusion... 5 04-18-2006 02:40 PM
cnc design mathematics vacpress CNCzone Club House 3 06-04-2004 08:22 PM




All times are GMT -5. The time now is 07:21 AM.





Powered by vBulletin® Version 3.8.7
Copyright ©2000 - 2012, vBulletin Solutions, Inc.
Content Relevant URLs by vBSEO
Template-Modifications by TMS

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353