IndHobby
01-11-2007, 05:10 PM
I am considering building a high performance CNC router, something in 9’x5’ size area. Something that can be run all day and go real fast. Sort of a gift to myself.
I am looking to rapid in the 1800 IPM range (maybe a little slower) so I’m looking for suggestions insofar as the drive design.
Right off the bat I know that ballscrews will not work.
So I am down to Rack and Pinion or Belt.
If I go with a standard rack design what is the tooth/pressure angle that is favored?
If I go with a belt design I’m looking at using 8mm x 20mm HTD, fixed on both ends with the X axis drive motors mounted on the gantry. There will be two motors for the X axis. I considered using a loop configuration with the X axis drive motors mounted on the table but I would need a belt 5.5 meters around. That is one big belt. So I am forced to put the motors on the gantry and deal with the extra mass.
As you can tell I like the belt idea a little more, I like belts, I understand them. A Rack and Pinion I’m not too sure about.
Now of course it’s the X axis I’m worried about. Moving the whole gantry is the hard part.
I know I am going to use 1000 in/oz peak servos, and some quick math gives me the following.
To get things down in the useful area the motors are reduced 4.1 to 1, so that give a useful torque of 4000 in/oz. The HTD pulley I like has a pitch diameter of 2.5 (or r 1.25).
4000in-oz /1.25” (radius) = 3200 oz of force = 200 lbs of force.
200 lbs of force x 2 motor for the X axis = 400 lbs of force.
I figure the gantry will weigh about 100 lbs.
After a little acceleration math I get an acceleration of 1544.35 inch/second^2
Peak velocity is 1800 IPM.
1800 IPM = 30 IPS
30 IPS (max speed) / 1544 (acceleration) = .02 seconds to reach max speed. (This is not the right way to do this section of the equation but it gives an idea).
Does anyone have any comments?
I am looking to rapid in the 1800 IPM range (maybe a little slower) so I’m looking for suggestions insofar as the drive design.
Right off the bat I know that ballscrews will not work.
So I am down to Rack and Pinion or Belt.
If I go with a standard rack design what is the tooth/pressure angle that is favored?
If I go with a belt design I’m looking at using 8mm x 20mm HTD, fixed on both ends with the X axis drive motors mounted on the gantry. There will be two motors for the X axis. I considered using a loop configuration with the X axis drive motors mounted on the table but I would need a belt 5.5 meters around. That is one big belt. So I am forced to put the motors on the gantry and deal with the extra mass.
As you can tell I like the belt idea a little more, I like belts, I understand them. A Rack and Pinion I’m not too sure about.
Now of course it’s the X axis I’m worried about. Moving the whole gantry is the hard part.
I know I am going to use 1000 in/oz peak servos, and some quick math gives me the following.
To get things down in the useful area the motors are reduced 4.1 to 1, so that give a useful torque of 4000 in/oz. The HTD pulley I like has a pitch diameter of 2.5 (or r 1.25).
4000in-oz /1.25” (radius) = 3200 oz of force = 200 lbs of force.
200 lbs of force x 2 motor for the X axis = 400 lbs of force.
I figure the gantry will weigh about 100 lbs.
After a little acceleration math I get an acceleration of 1544.35 inch/second^2
Peak velocity is 1800 IPM.
1800 IPM = 30 IPS
30 IPS (max speed) / 1544 (acceleration) = .02 seconds to reach max speed. (This is not the right way to do this section of the equation but it gives an idea).
Does anyone have any comments?